Question on alien upgrades
Longtooth
Join Date: 2002-07-02 Member: 863Members
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Soooo you can be a level3 and take adrenaline (movement), but respawn, go level1, and evolve Silence instead.
Soooo you can be a level3 and take adrenaline (movement), but respawn, go level1, and evolve Silence instead.<!--QuoteEnd--></td></tr></table><span id='postcolor'><!--QuoteEEnd-->
I thought coil answered it rather nicely.
-Ryan!
"Bad men live that they may eat and drink,
whereas good men eat and drink that they may live."
-- Socrates
Three chambers, one from each...
No matter. The question has been answered.
-Ryan!
"A woman's appetite is twice that of a man's;
her sexual desire, four times; her intelligence, eight times."
-- Sanskrit proverb
<!--EDIT|Moleculor|Aug. 02 2002,22:01-->
Random side note:
5 aliens, 3 different upgrade chambers, each with 3 options
5x3x3x3 = <b>135 possible alien combinations!</b>
so to be more complete, 5 aliens, 3 upgrade chambers, 3 options from each (choose one only), and anywhere from 1-3 hives. hmmmm I'll edit this later when I've actually decided to put this through set theory to make sure it's so simple
edit: having just looked at the stories, it may be the number of chambers not hives, someone help me out here eh? It might be necessary info.
re-edit: I'll just assume chambers. Since you may only choose one upgrade out of three per chamber, that's 3c1 = 3. For any one upgrade, you have 3 possible states. Also you won't necessarily have any chambers available, or just haven't upgraded, that makes a summation from 0 to 3 on used chambers. So with each single type of chamber, there are 3*3 = 9 forms of upgrades, and 5 aliens to combine with, that makes 5*{[x=0,3]E(x*9)} = 270 possible combinations
<span style='color:red'>5 alien classes</span> x <span style='color:yellow'>(3 defensive upgrade choices x 3 levels of upgrade)</span> x <span style='color:lightgreen'>(3 movement x 3 levels)</span> x <span style='color:orange'>(3 sensory x 3 levels)</span>
<span style='color:lightblue'><b>= 3,645 possible combinations of alien, upgrades, and ability levels.</b></span>
<!--EDIT|Fam|Aug. 03 2002,19:58-->
5 alien classes x (3 defensive upgrade choices x 4 levels of upgrade) x (3 movement x 4 levels) x (3 sensory x 4 levels) = 8640
<!--EDIT|Comprox|Aug. 03 2002,12:55-->
<!--EDIT|coil|Aug. 03 2002,15:22-->
providing the lack of any further mistakes
new possible equation is
5*{[x=0,3]E(9^x)} = 4100
been a while since last semester, still might be wrong but, heh.
5 + 5*9 + 5*9 + 5*9 + 5*9^2 + 5*9^2 + 5*9^2 + 5*9^3
With NO CHAMBERS AVAILABLE:
5
With ONE CHAMBER AVAILABLE, aliens can go D, M, or S.
D: 5x9 = 45
M: 5x9 = 45
S: 5x9 = 45
With TWO CHAMBERS AVAILABLE:
D & M: 5x9x9 = 405
D & S: 5x9x9 = 405
M & S: 5x9x9 = 405
With THREE CHAMBERS AVAILABLE:
D & M & S: 5x9x9x9 = 3,645
When you add all those options together, the grand total is
<span style='color:lightblue'><b>FIVE THOUSAND POSSIBLE ALIEN COMBINATIONS.</b></span> Nice.
BTW, any math wiz who can translate that into a succinct mathematical formula, please do so.
5*{[X=0,3]SUM((3cX)*9^X)}
edit: note that 3cX is "3 choose X"
it's an equation that will tell you how many combinations are in a set where you have in this case 3 available, and you want to choose x from that (this eliminates separating it out into individual cases as was done in the previous post). Also note that this is not used if the order matters, in that case you would use permutation not choose.