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MrMojoMrMojo Join Date: 2002-11-25 Member: 9882Members, Constellation
<div class="IPBDescription">Do my assignments for me</div> Hey isn't it great, I have an extra credit assignment I don't understand and I'm sure you'll all be happy to help me.

<b>Determine your density</b>

And yes, I know that d = m/v and I know I can get my own mass, but aside from jumping in a tub I have no idea how to get my volume or density.


So help me.

Comments

  • TychoCelchuuuTychoCelchuuu Anememone Join Date: 2002-03-23 Member: 345Members
    Dip your finger in a cup of water, measure the displacement. Estimate from that point forward.

    Or just Google "average human density."
  • JediYoshiJediYoshi The Cupcake Boss Join Date: 2002-05-27 Member: 674Members
    <a href='http://web.ask.com/web?q=what+is+my+density&qsrc=1&o=0' target='_blank'>Ask Jeeves?</a>
  • WarningForeverWarningForever Join Date: 2004-05-06 Member: 28503Members
    There's really no other way to get volume precisely without jumping in a fluid, unless you're a big math fan and want to measure every part of your body. So I'm not sure I can help you there.

    Weight is easy, however: Get on a scale, record weight

    If all else fails, get a "cheat sheet" online, w/ the average weights, volumes, and body densities of your age group. (I dunno, google it)
  • MrMojoMrMojo Join Date: 2002-11-25 Member: 9882Members, Constellation
    ok well roadmaster already helped me but you guys can keep going
  • ToneeTonee Wub wuB UK Join Date: 2003-10-25 Member: 21926Members, Constellation
  • RellixRellix Join Date: 2003-02-15 Member: 13572Members, Constellation, Reinforced - Shadow
    Lie about actualy doing it and just guess.

    Its not like they can check.
  • ZelZel Join Date: 2003-01-27 Member: 12861Members
    jump in a tub for extra credit you stinky gamer.

    mark the line the water comes to, get out slowly so as not to carry much water out, then refill the tub with gallon jugs until it reaches the line? that could take too much water. so find a better way.
  • NumbersNotFoundNumbersNotFound Join Date: 2002-11-07 Member: 7556Members
    How about you "estimate" by drawing an outline of yourself on the street, measuring the area, then multiplying by your approximate depth.

    Or, for more accuracy, take your depth in segments, with each body part being a different depth. Arms, legs lower torso, upper torso, head, pelvis should be good enough.
  • OttoDestructOttoDestruct Join Date: 2002-11-08 Member: 7790Members
    <!--QuoteBegin-404NotFound+Nov 7 2004, 03:57 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td><b>QUOTE</b> (404NotFound @ Nov 7 2004, 03:57 PM)</td></tr><tr><td id='QUOTE'><!--QuoteEBegin--> How about you "estimate" by drawing an outline of yourself on the street, measuring the area, then multiplying by your approximate depth.

    Or, for more accuracy, take your depth in segments, with each body part being a different depth. Arms, legs lower torso, upper torso, head, pelvis should be good enough. <!--QuoteEnd--> </td></tr></table><div class='postcolor'> <!--QuoteEEnd-->
    And then for added fun put some bullet casings and blood along the outline.
  • RellixRellix Join Date: 2003-02-15 Member: 13572Members, Constellation, Reinforced - Shadow
    <!--QuoteBegin-OttoDestruct+Nov 7 2004, 08:59 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td><b>QUOTE</b> (OttoDestruct @ Nov 7 2004, 08:59 PM)</td></tr><tr><td id='QUOTE'><!--QuoteEBegin--> <!--QuoteBegin-404NotFound+Nov 7 2004, 03:57 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td><b>QUOTE</b> (404NotFound @ Nov 7 2004, 03:57 PM)</td></tr><tr><td id='QUOTE'><!--QuoteEBegin--> How about you "estimate" by drawing an outline of yourself on the street, measuring the area, then multiplying by your approximate depth.

    Or, for more accuracy, take your depth in segments, with each body part being a different depth. Arms, legs lower torso, upper torso, head, pelvis should be good enough. <!--QuoteEnd--></td></tr></table><div class='postcolor'><!--QuoteEEnd-->
    And then for added fun put some bullet casings and blood along the outline. <!--QuoteEnd--> </td></tr></table><div class='postcolor'> <!--QuoteEEnd-->
    And do not cross tape.
  • ElectricSheepElectricSheep Join Date: 2003-04-21 Member: 15716Members
    <!--QuoteBegin-Theki11er+Nov 7 2004, 02:45 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td><b>QUOTE</b> (Theki11er @ Nov 7 2004, 02:45 PM)</td></tr><tr><td id='QUOTE'><!--QuoteEBegin--> There's really no other way to get volume precisely without jumping in a fluid, unless you're a big math fan and want to measure every part of your body. So I'm not sure I can help you there.

    Weight is easy, however: Get on a scale, record weight

    If all else fails, get a "cheat sheet" online, w/ the average weights, volumes, and body densities of your age group. (I dunno, google it) <!--QuoteEnd--> </td></tr></table><div class='postcolor'> <!--QuoteEEnd-->
    Mass != Weight. Mss is the amount of matter you have, weight is the gravitational force that is exerted on that mass. For example, something on the moon has less weight then the same thing on Earth, but it has the same mass.
  • im_lostim_lost TWG Rule Guru Join Date: 2003-04-26 Member: 15861Members
    Mass doesn't equal weight, but since this is all on Earth, with a (nearly) constant gravitational field, they are interchangible.

    You could put water in a tub, mark the line, get in, mark a new line, then get out. Find the area by multiplying L x W x H (assuming a rectangular tub). It sounds simple enough, though if it were me, I wouldn't bother with doing it (since it is extra credit and actually involves some effort).
  • TychoCelchuuuTychoCelchuuu Anememone Join Date: 2002-03-23 Member: 345Members
    <!--QuoteBegin-Rellix+Nov 7 2004, 06:14 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td><b>QUOTE</b> (Rellix @ Nov 7 2004, 06:14 PM)</td></tr><tr><td id='QUOTE'><!--QuoteEBegin--> <!--QuoteBegin-OttoDestruct+Nov 7 2004, 08:59 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td><b>QUOTE</b> (OttoDestruct @ Nov 7 2004, 08:59 PM)</td></tr><tr><td id='QUOTE'><!--QuoteEBegin--> <!--QuoteBegin-404NotFound+Nov 7 2004, 03:57 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td><b>QUOTE</b> (404NotFound @ Nov 7 2004, 03:57 PM)</td></tr><tr><td id='QUOTE'><!--QuoteEBegin--> How about you "estimate" by drawing an outline of yourself on the street, measuring the area, then multiplying by your approximate depth.

    Or, for more accuracy, take your depth in segments, with each body part being a different depth. Arms, legs lower torso, upper torso, head, pelvis should be good enough. <!--QuoteEnd--></td></tr></table><div class='postcolor'><!--QuoteEEnd-->
    And then for added fun put some bullet casings and blood along the outline. <!--QuoteEnd--></td></tr></table><div class='postcolor'><!--QuoteEEnd-->
    And do not cross tape. <!--QuoteEnd--> </td></tr></table><div class='postcolor'> <!--QuoteEEnd-->
    Or cut out all this dang work and just shoot a hobo.
  • HazeHaze O RLY? Join Date: 2003-07-07 Member: 18018Members, Constellation
    Bull**** your way through.
  • ThansalThansal The New Scum Join Date: 2002-08-22 Member: 1215Members, Constellation
    <!--QuoteBegin-i'm lost+Nov 7 2004, 04:41 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td><b>QUOTE</b> (i'm lost @ Nov 7 2004, 04:41 PM)</td></tr><tr><td id='QUOTE'><!--QuoteEBegin--> You could put water in a tub, mark the line, get in, mark a new line, then get out. Find the area by multiplying L x W x H (assuming a rectangular tub). It sounds simple enough, though if it were me, I wouldn't bother with doing it (since it is extra credit and actually involves some effort). <!--QuoteEnd--> </td></tr></table><div class='postcolor'> <!--QuoteEEnd-->
    that is it.

    simple aint it?
  • ThE_HeRoThE_HeRo Join Date: 2003-01-25 Member: 12723Members
    <!--QuoteBegin-Thansal+Nov 7 2004, 06:09 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td><b>QUOTE</b> (Thansal @ Nov 7 2004, 06:09 PM)</td></tr><tr><td id='QUOTE'><!--QuoteEBegin--> <!--QuoteBegin-i'm lost+Nov 7 2004, 04:41 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td><b>QUOTE</b> (i'm lost @ Nov 7 2004, 04:41 PM)</td></tr><tr><td id='QUOTE'><!--QuoteEBegin--> You could put water in a tub, mark the line, get in, mark a new line, then get out.  Find the area by multiplying L x W x H (assuming a rectangular tub).  It sounds simple enough, though if it were me, I wouldn't bother with doing it (since it is extra credit and actually involves some effort). <!--QuoteEnd--></td></tr></table><div class='postcolor'><!--QuoteEEnd-->
    that is it.

    simple aint it? <!--QuoteEnd--> </td></tr></table><div class='postcolor'> <!--QuoteEEnd-->
    I think making it up would be simpler. Here, let me help you:

    45.32kg/m
  • john_sheujohn_sheu Join Date: 2004-02-26 Member: 26917Members
    I would think that most terrestrial mammals have the same density. Thus you could try it with a small dog, or hamster. Procedure:
    1. Obtain hamster.
    2. Measure volume of common drink mug.
    3. Completely fill with water.
    4. Completely dunk hamster.
    5. Remove hamster.
    6. Measure volume lost.

    etc.
  • im_lostim_lost TWG Rule Guru Join Date: 2003-04-26 Member: 15861Members
    If you're going to make it up, use something closer to 120 kg/m^3. The average human doesn't come close to 1 m^3 in volume.
  • KillymageeKillymagee Join Date: 2002-11-01 Member: 3136Members
    Well to us bodybuilders,

    2+2= dumbell

    so I say my "density" is dumbell. <!--emo&:p--><img src='http://www.unknownworlds.com/forums/html//emoticons/tounge.gif' border='0' style='vertical-align:middle' alt='tounge.gif' /><!--endemo-->
  • Har_Har_the_PirateHar_Har_the_Pirate Join Date: 2003-08-10 Member: 19388Members, Constellation
    fill your tub with 5 gallon tubs of water or gas than jump in.... other than that i dont know
  • Cold_NiTeCold_NiTe Join Date: 2003-09-15 Member: 20875Members
    Fail your assignment.
  • BulletHeadBulletHead Join Date: 2004-07-22 Member: 30049Members
    <!--QuoteBegin-i'm lost+Nov 7 2004, 04:41 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td><b>QUOTE</b> (i'm lost @ Nov 7 2004, 04:41 PM)</td></tr><tr><td id='QUOTE'><!--QuoteEBegin--> Mass doesn't equal weight, but since this is all on Earth, with a (nearly) constant gravitational field, they are interchangible.

    You could put water in a tub, mark the line, get in, mark a new line, then get out. Find the area by multiplying L x W x H (assuming a rectangular tub). It sounds simple enough, though if it were me, I wouldn't bother with doing it (since it is extra credit and actually involves some effort). <!--QuoteEnd--> </td></tr></table><div class='postcolor'> <!--QuoteEEnd-->
    Most tubs are NOT rectangular tho... the one end is a 45* slope, the corners are rounded, AND the tub itself is at aroudn a 5* slope... so you'd have a fair margin of error there...

    best thing I can think of would be to buy a PARABOLIC swimming pool (one of those little kiddy pools... make sure it has at LEAST 2 foot high sides) and fill it all of the way up. Then, just SLOWLY get in. COMPLETELY submerge yourself. Then, get out SLOWLY. Use a 5 gallon and a 1 gallon container to see how many gallons you misplaced. then, calculate the area of the water (find a box, fill it with ONE gallon of water, and find the area of the dimensions)

    SHOULD work... but it's NOT gonna be a pretty equation... and it'll take the better part of an afternoon...
  • fried_ricefried_rice Join Date: 2004-09-10 Member: 31582Banned
    edited November 2004
    I think there's a formula in my physics book for a totally submerged object that states

    V1/V2 = D2/D1

    where V1 is the volume of the water <b>displaced by your body</b>, V2 is the volume of water, D2 is the density of your body, and D1 is the density of water
    (1000 kg/m^3).

    First though, you need the volume of water in the tub. So measure the height of the water and take the dimensions of the length and width of the tub. That should get you your V2.

    A really clever way to do this is to use the suggestion given before: mark the height of the water in the tub <b>without you in it </b>and then jump in and mark the height of the water in the tub with you in it. now take this difference (h = new height - original height) and put it into the volume formula for a rectangle (V1 = l x w x h) to get the volume of water displaced by you, where l and w are the length and width of the tub respectively.

    So now you should be able to determine your body's density by substitution: D2=(V1xD1)/V2.

    To get the actual volume of your body, take the density you found of yourself, and, knowing your mass (in kilograms), substitute the numbers into D=M/V to get it.

    Now its not precise because a bath tub is not a perfect rectangle, the answer you get won't be exact but will be a good approximation.
  • fried_ricefried_rice Join Date: 2004-09-10 Member: 31582Banned
    edited November 2004
    hmm if you can take the difference in the volumes, which might actually be your body's volume ( i forgot what the variabiles represent now ), you can get the density.
  • Jim_has_SkillzJim_has_Skillz Join Date: 2003-01-19 Member: 12475Members, Constellation
    <!--QuoteBegin-fried_rice+Nov 7 2004, 09:19 PM--></div><table border='0' align='center' width='95%' cellpadding='3' cellspacing='1'><tr><td><b>QUOTE</b> (fried_rice @ Nov 7 2004, 09:19 PM)</td></tr><tr><td id='QUOTE'><!--QuoteEBegin--> I think there's a formula in my physics book for a totally submerged object that states

    V1/V2 = D2/D1

    where V1 is the volume of the water <b>displaced by your body</b>, V2 is the volume of water, D2 is the density of your body, and D1 is the density of water
    (1000 kg/m^3).

    First though, you need the volume of water in the tub. So measure the height of the water and take the dimensions of the length and width of the tub. That should get you your V2.

    A really clever way to do this is to use the suggestion given before: mark the height of the water in the tub <b>without you in it </b>and then jump in and mark the height of the water in the tub with you in it. now take this difference (h = new height - original height) and put it into the volume formula for a rectangle (V1 = l x w x h) to get the volume of water displaced by you, where l and w are the length and width of the tub respectively.

    So now you should be able to determine your body's density by substitution: D2=(V1xD1)/V2.

    To get the actual volume of your body, take the density you found of yourself, and, knowing your mass (in kilograms), substitute the numbers into D=M/V to get it.

    Now its not precise because a bath tub is not a perfect rectangle, the answer you get won't be exact but will be a good approximation. <!--QuoteEnd--> </td></tr></table><div class='postcolor'> <!--QuoteEEnd-->
    physics problem = owned
  • UnderDOGUnderDOG Join Date: 2003-04-05 Member: 15221Members
    edited November 2004
    I think that I'm going to say the average person has about 5 liters of blood, and that blood is about a tenth of their total liquid. Humans are said to be about 60-70 percent water (by volume I’m hoping), so ill say a human takes up about 70 liters of space. I weight about 160 pounds (which I consider average), which is around 72 kg. So my density is 72kg/ 70 liters. Convert to g/ml and you have 72g/ 70ml, which comes to about 1.02 g/ml as an average human density.
  • fried_ricefried_rice Join Date: 2004-09-10 Member: 31582Banned
    that works too but you gotta search for all the values somewhere.
  • marcemarce Join Date: 2004-08-24 Member: 30869Members
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